Question

The normality of solution obtained by mixing
100 ml of 0.2 M H2S04 with 100 ml of 0.2 M
NaOH is​

Answer 1

Answer:

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Answer 2

Explanation:

Normality = molarity x n factor

Total volume = 100 + 100 = 200ml

n factor of H2SO4 IS 2

N1 = 0.2X2 = 0.4 normal

n factor of NaOH = 1

N2 = 0.2x1 = 0.2 normal

By dilution formula -

NV = N1V1 + N2V2

Nx0.2 =0.4x0.1 + 0.2x0.1 = 0.04 + 0.02

N = 0.06/0.2

N = 0.3 normal.

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