the normality of the 0.4 gram of naoh are present in the 250ml of solution
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Answer:
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Explanation:
What is the molarity of 4 grams of NaOH dissolved in 250 ml of solution?
The Molariry = moles of solute/volume of solution in litres ..
in order to find the moles from the mass we need to find the molar mass..
molar mass for NaOH= ( 22.9+16+1) respectively =39 g/mol
by using this simple equation we can calculate the moles of Naoh
moles= mass/ molar mass
moles=4g/39g/mole
=o.1 mole.. make sure to cancel the g with g during calculation .
now I have the moles and I have the volume I can calculate the molarity, but I have one simple problem that the volume is in (ml )and is supposed to be in (liter).
1 litre=1000ml
simple divide what we have over what we want
250 ml/1000 liter =0.25 litre yay
Now execute
molarity= moles/ volume
Molarity =0.1 mole/0.25 liter
=0.4 M or mole/liter.. don't forget to write the measurement unit for molarity to get extra grade ..