The nth term AP of the sequence is 2n - 3. Is the sequence an A.P? If so find its 8th term.
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If we put n=1,n=2,n=3, then
T(n)=2n-3
T(1)=2-3=-1
T(2)=4-3=1
T(3)=6-3=3
There is common difference d=2
So, it is in A.P.
T(8)=16-3=13
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