Question

The nth term of a progression is 3n2 + 4. Is the pattern of numbers so formed in A.P.!
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Answer 1

Step-by-step explanation:

$a(1) = {3n}^{2} + 4 \\ = 3(1) {}^{2} + 4 \\ = 3 + 4 = 7$

So 1 st term of progession is 7 .

$2nd \: term = {3(2)}^{2} + 4 \\ = 12 + 4 = 16$

$3rd \: term = {3(3)}^{2} + 4 \\ = 27 + 4 = 31$

Here in progession

$7 \times 1 + 0 \\ 7 \times 2 + 2 \\ 7 \times 3 + 3.....$

Answer 2

Answers -28,-3

Step-by-step explanation: