The nth term of a sequence is (2n-3) , find its fifteenth term
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Answered by
8
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nth term is equal to. a+(n-1)d
a+(n-1)d= 3n + 5
On opening bracket
dn + (a-d)= 3n + 5.
On comparing both the sides.
dn= 3n therefore d=3.
Also a-d = 5
a-3 =5
a= 8
fifteenth term = 8+ (15–1)×3
fifteenth term = 8+ 42
The answer is 50
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⬇️HERE IS YOUR ANSWER⬇️
_______________________
nth term is equal to. a+(n-1)d
a+(n-1)d= 3n + 5
On opening bracket
dn + (a-d)= 3n + 5.
On comparing both the sides.
dn= 3n therefore d=3.
Also a-d = 5
a-3 =5
a= 8
fifteenth term = 8+ (15–1)×3
fifteenth term = 8+ 42
The answer is 50
HOPE THIS ANSWER HELPS YOU
MARK AS BRAINLIEST ✌✌
_______×××××_______
siddhitiwari:
It's wrong
The answer must be 27
Answered by
2
Answer: 15th term = 27
Step-by-step explanation:
since
nth term =(2n-3)
then 15th term=2x15-3
= 30 - 3
= 27
hence answer is =27
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