Question

the nth term of a sequence is 3n-2.is the sequence an A.P.?If so,find its10th term.


#maths10th
#A.P.​

Answer 1

SOLUTION:-

Given:

The nth term of a sequence is 3n-2.

${}^{a} n - {}^{a} n - 1 = constant$

Therefore,

${}^{a} n = 3n - 2 \\ \\ {}^{a} n - 1 = 3(n - 1) - 2 \\ \\ = > 3n - 3 - 2 \\ \\ = > 3n - 5$

So,

${}^{a} n - {}^{a} n - 1 \\ = > 3n - 2 - (3n - 5) \\ = > 3n - 2 - 3n + 5 \\ = > - 2 + 5 \\ = > 3$

A.P. is 3.

Now,

10th term;

${}^{a} 10 = 3(10) - 2 \\ \\ = > 30 - 2 \\ \\ = > 28$

Hope it helps ☺️

Answer 2

Answer:

920nth

Step-by-step explanation: