The nth term of a sequence is given by 2n + 1. Write down the first four terms of the sequence. 37,19
(b) The first four terms of another sequence are 1, 7, 17, 31.
(0) By comparing this sequence with the sequence in (a), write down, in terms of n, a formula for the nt
term of the sequence.
In = 2n +12
(ii) Hence, find the 388 term.
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Answer:
6x
2
+17x+5
6x
2
+2x+15x+5
2x(3x+1)+5(3x+1)
(2x+5)(3x+1)
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