Question

The nth term of a sequence is given by xn =3n2-1 which term of the sequence is equal to 866

Answer 1

Answer:

given nth term of a sequence

An = 3n^2 - 1 and An = 866

to find n

3n^2 - 1 = 866

3n^2 = 867

n^2 = 867/3

n^2 = 289

n = √289

n = 17 answer

Answer 2

Answer:

866 is 17th term in series

Step-by-step explanation:

Given,

The nth term of a sequence is given by

$x_{n} =3n^{2} -1$

nth term  is 866

$x_{n} =3n^{2} -1$=866

we have to calculate which nth in series

$3n^{2}-1=866\\3n^{2} =867\\n^{2} =\frac{867}{3} \\n^{2} =289\\n=\sqrt{289} =17$

866 is 17th term in series

#SPJ2