Question

the nth term of an A.P is (3n-2),find it's first term​

Answer 1

Answer:

1

Step-by-step explanation:

reshuffle the term

3n-2

=-2+3(n-1+1)

=-2+3(n-1)+3

=1+(n-1)3

comparing with Tn= a+(n-1)d

a=1

Answer 2

Answer:

Concept: rearranging the given figure in the formulae of A.P.

GIVEN: (3n-2)

TO FIND: find the first term

Step-by-step explanation:

rearranging the nth term (3n-2) in the formulae of a+(n-1)d

so, $-2+3(n-1+1)$

so,$-2+3(n-1)+3$

so, $1+(n-1)3$

therefore, of we compare with a+(n-1)d,

a= 1

hence, first term is 1.

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