The nth term of an A.P is given by (−4n + 15), Find the sum of first 20 terms of this A.P.
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Answered by
56
Answer:
The sum of first 20 terms of AP is - 540.
Step-by-step explanation:
Given :
nth term of an A.P, (an) = - 4n + 15……..(1)
On putting n = 1, 2,3 ,…. in eq (1),
For n = 1
(an) = - 4n + 15
1 = - 4(1) + 15
a1 = 11
For n = 2
a2 = - 4(2) + 15
a2 = - 8 + 15
a2 = 7
Common Difference , d = a2 - a1
d = 7-11
d = - 4
By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d]
S20 = (20/2)[2 × 11 + (20 -1)(-4)]
S20 = 10 [22 + 19 × - 4[
S20 = 10 [22 - 76]
S20 = 10 × - 54
S20 = - 540
Hence, the sum of first 20 terms of AP is - 540.
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Answer:
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