Question

the nth term of an A.P is given by Tn=4n-3. find the sum of first 60 terms of an A.P.

Answer 1

a=4(1)-3
a=1
A2=4(2)-3
A2=5
d=4
S60=30(2+59(4))
S60=30(2+236)
S60=30(238)
S60=7140
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hope this will help you

Answer 2

Answer:

7140

Step-by-step explanation:

a=4(1)-3

a=1

A2=4(2)-3

A2=5

d=4

S60=30(2+59(4))

S60=30(2+236)

S60=30(238)

S60=7140