The nth term of an AP is 1+2n. What is the sum up to the first 20 terms
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Step-by-step explanation:
Given,
tn = 1 +2n
=> a+(n-1) d = 1 + 2n
a + (n-1) d = 3 + 2n - 2 = 3 + (n-1) 2
a = 3; d = 2
So,
S(20) = 10/2 [ 2(3) + ( 20 - 1) 2] = 5 ( 6 + 38 )
S(20) = 220
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