Question

The nth term of an AP is 3+2n the sum and product of its 3rd and 5th terms are .....​

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{The n th term of an A.P is 3+2n}$

$\underline{\textbf{To find:}}$

$\textsf{Sum and product of its 3 rd and 5 th term}$

$\underline{\textbf{Solution:}}$

$\mathsf{t_n=3+2n}$

$\mathsf{For\;n=3,\;\;t_3=3+2(3)=3+6=9}$

$\mathsf{For\;n=5,\;\;t_3=3+2(5)=3+10=13}$

$\mathsf{Now,}$

$\mathsf{t_3+t_5=9+13=22}$

$\mathsf{t_3{\times}t_5=9{\times}13=117}$

Answer 2

Answer:

Sum=22

Product=117.

Step-by-step explanation:

Given:- nth term of AP is 3 + 2n.

To Find:- Sum and product of3rd and th term.

Solution:-

tₙ=3+2n,

∵$t_{3}$=3+2(3)=9 and $t_{5}$=3+2(5)=13

now,

Sum=$t_{3}$ + $t_{5}$=9+13=22

Product=$t_{3}$*$t_ {5}$ =9*13=117.

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