The nth term of an ap is 3n+1 .The sum of its first n terms is
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Step-by-step explanation:
nth term = 3n+1
when n= 1---- nth term =4
n=2-------7
n=3-----10
so a=1,d=3;
sum = n/2 (2a+(n-1)d)
= n/2(8+(n-1)3)
where n= nth term
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