Question

The nth term of an AP is 3n-1, what is the of S₂?.

Answer 1

n=1
a1=3n-1=3×1-1
10a1==3-1=2
a2=3n-1
=3×2-1
=6-1
a2 =5
a3=3n-1
=3×3-1
=9-1
a3=8
d=a3-a2=a2-10a1
=8-5=5-2=3
d=3
sn=n/2[2a+(n-1)d]
s2=2/2[2×2+(2-1)3]
s2=1(4+3)
s2=7

Answer 2

Step-by-step explanation:

Given t

n

=3n−1

To find the series, we will plug in numbers in the above expression.

For n = 1, 3n - 1 = 2

n = 2, 3n - 1 = 5

n = 3, 3n - 1 = 8

So, the sequence we get is 2, 5, 8, 11, .....

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