Question

the nth term of an ap is 4n-5 find the sum of 25 terms

Answer 1

Step-by-step explanation:

first term=4*1-5=-1

second term=4*2-5=3

third term=4*3-5=7

we know,

a=-1,r=t2-t1=3-(-1)=3+1=4,n=25

sum of 25 terms is,

S=n/2(2a+(n-1)d)

S=25/2(2*-1+(25-1)4)

=(25*94)/2

=2350/2

=1175. (ans)

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