the nth term of an ap is 8-5n . find the sum of n terms
Answers
Answered by
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Step-by-step explanation:
Tn= 8-5n
on putting n=1 we get
T1= 8-5×1
T1= 8-5
T1= 3
T1=a=3
Sn= n/2(a+l) {here l is last term}
= n/2(3+8-5n)
= n/2(11-5n)
= 11n/2-5n²/2
#666
Answered by
0
Step-by-step explanation:
T n=8-5n
on n=1 we get
T1=8-5×1
T1=8-5
T1=3
T1=a=3
sn=n/2(a+1)
=n/2(3+8-5n)
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