The nth term of an AP is an=2n+1 , find its sum
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If the nth term of an AP is an=2n+1
then,
first term=2(1)+1
=2+1
=3
second term=2(2)+1
=4+1
=5
common difference= 5-3
= 2
sum of an AP is=n/2(2a+(n-1)d)
=n/2(2(3)+(n-1)2)
=n/2(6+2n-2)
=n/2(4+2n)
=n(2+n)
=2n+n2(square)
sum of the AP is 2n+n2.
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