The nth term of an AP is given by tn=a+bn. show that it is an AP. Find its first term and common difference.
Answers
Answered by
4
Step-by-step explanation:
nth term of a.p
tn= 3n+4
put value of n = 1,2,3
n= 1
t1= 3×1+4= 3+4=7
n= 2
t2=3×2+4=6+4=10
n=3
t3=3×3+4=9+4=13
to find difference t2-t1
10-7=3
t3-t2
13-10=3
so the difference is 3
sum of the first five term
s=n/2[2a+(n-1)d]
s1=1/2[2×7+(1-1)3]
s1=1/2(14+0)
s1=1×7
s1=7
Similar questions