The nth term of an AP is Tn = 2n + 1 ; find the Ap
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Given,
Tn=2n + 1
then,
T1 = 2(1) + 1
= 2+1=3
T2=2(2) + 1
= 4 +1=5
T3=2(3) +1
= 6+1= 7
T4 = 2(4) +1
= 8 +1=9
therefore, the AP is 3,5,7,9,.............
Tn=2n + 1
then,
T1 = 2(1) + 1
= 2+1=3
T2=2(2) + 1
= 4 +1=5
T3=2(3) +1
= 6+1= 7
T4 = 2(4) +1
= 8 +1=9
therefore, the AP is 3,5,7,9,.............
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