The nth term of an arithmetic progression is 3n-1.Find the progression.
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As tthe nth term is 3n-1
put n=1,2,3.... and you get the progression
putting n=1,2,3,4.... we get
3(1)-2,3(2)-2,3(3)-2,3(4)-2
or,1,4,7,10..... is the required progression.
Thank you
put n=1,2,3.... and you get the progression
putting n=1,2,3,4.... we get
3(1)-2,3(2)-2,3(3)-2,3(4)-2
or,1,4,7,10..... is the required progression.
Thank you
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