Question

The nth term of an arithmetic Progression
is 4n²-1. The 2nd team is.​

Answer 1

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Answer :

$a_n=4n^2-1\\\\a_1=4(1)^2-1\\\\=>a_1=3\\\\a_2=4(2)^2-1\\\\=>a_2=4(4)-1\\\\=>a_2=16-1\\\\=>a_2=15$

So 2nd term = 15

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