The nth term of an arithmetic sequence is 5-6n Find the sum of its 1st n terms
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Answer:
Step-by-step explanation:
a1=5-6
= -1
a2= 5-12
=-7
d=-7-(-1)
=-6
Sn=n/2[2a+(n-1)d]
= n/2[-2-6n+6]
=n/2[4-6n]
=n(2-3n)
= 2n-3n^2
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