Question

The nth term of an arithmetic sequence is 6n+11 find the common difference

Answer 1

Answer:

USING HIT AND TRIAL METHOD

let n be 1,2,3,4

so 6n+11=6*1+11=6+11=17

6n+11=6*2+11=12+11=23

6n+11=6*3+11=18+11=29

6n+11=6*4+11=24+11=35

here A1=17, A2=23,A3=29,A4=35

Here,

a2-a1=23-17=6

a3-a2=29-23=6

a4-a3=35-29=6

HERE ALL HAVE THE DIFFERENCE OF 6

SO

d=6