Question

The nth term of AP 1/1.2,1/2.3,1/3.4will be​

Answer 1

Answer:

it's nth term is 1.22 - 0.39n

Step-by-step explanation:

refer the image.

hope it helped.

Answer 2

The nth tern of A.P=$an_n=1.23-0.399n$

Step-by-step explanation:

Given A.P

1/1.2,1/2.3,1/3.4

$a=a_1=\frac{1}{1.2}$

$a_2=\frac{1}{2.3}$

A.P: When the difference between two consecutive terms is constant then, the sequence is called A.P

$d=a_2-a_1=\frac{1}{2.3}-\frac{1}{1.2}=-0.399$

$a_n=a+(n-1)d$

Substitute the values then we get

$a_n=\frac{1}{1.2}+(n-1)(-0.399)=\frac{1.2}-0.399n+0.399=1.23-0.399n$

Therefore,nth tern of A.P=$an_n=1.23-0.399n$

#Learns more:

https://brainly.in/question/1360154:Answered by Brunila