the nth term of Ap is 2n+1 find sum three sums
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Answered by
5
heyyy !!
its me Nishant Mishra!!
your solution:
given: nth term is 2n+1
then,
first term =2(1)+1=>3
second term=2(2)+1=>5
here d=5-3=>2
now,
sum of first 3 terms => n/2{2a+(n-1)d}
=3/2{2×3+(2)2}
=3/2×10
=15
HOPE IT HELP!!!
its me Nishant Mishra!!
your solution:
given: nth term is 2n+1
then,
first term =2(1)+1=>3
second term=2(2)+1=>5
here d=5-3=>2
now,
sum of first 3 terms => n/2{2a+(n-1)d}
=3/2{2×3+(2)2}
=3/2×10
=15
HOPE IT HELP!!!
NishantShandilya:
plz mark as brianliest
Answered by
4
Hey there!
n th term of an A. P = 2n+1 .
1st term = 2(1)+1 = 3
2nd term = 2(2)+1 = 5 .
Common difference = 5 - 3 = 2 .
Sum of n terms = n/2 [ 2a + (n-1)d ]
Sum of 3 terms = 3/2 [ 2(3)+ (2)(2) ]
= 3/2[ 6 + 4 ]
= 3/2 [ 10]
= 3 * 5
= 15
Hope helped!
n th term of an A. P = 2n+1 .
1st term = 2(1)+1 = 3
2nd term = 2(2)+1 = 5 .
Common difference = 5 - 3 = 2 .
Sum of n terms = n/2 [ 2a + (n-1)d ]
Sum of 3 terms = 3/2 [ 2(3)+ (2)(2) ]
= 3/2[ 6 + 4 ]
= 3/2 [ 10]
= 3 * 5
= 15
Hope helped!
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