the nth term of
AP is an= 2n+1 find it's sum
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nth term of the AP = 2n + 1
Thus,
It's first term = 2(1) + 1 = 3
Second term = 2(2) + 1 = 5
Third term = 2(3) + 1 = 7
and so on......
Thus, the AP is:
AP = 3, 5, 7, .........
Here, First term (a) = 3
Common Difference (d) = 5-3 = 2
Sum up to = n terms.
Hence,
Sum = n/2{2a + (n-1)d}
= n/2{2(3) + (n-1)2}
= n/2(6 + 2n - 2)
= n/2(4 + 2n)
= n(n + 2)
Hence, sum of the given AP is n(n+2).
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