The nth
term of the A.P. (1 + √3), (1 + 2√3), (1 + 3√3), ... is
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given a =1+√3
d = (1+2√3) - 1+√3
d = √3
9th term is
1+√3 + (9-1) ×√3
1+√3 + 8 ×√3
9 + 2√3 answer
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