Question

The nth term of the A.P. (7n-6). find the series.

Answer 1

Answer:

nth term of a series = 7n - 6

Substituting n = 1, we get,

⇒ 7 ( 1 ) - 6  = 7 - 6 = 1

Substituting n = 2, we get,

⇒ 7 ( 2 ) - 6 = 14 - 6 = 8

Substituting n = 3, we get,

⇒ 7 ( 3 ) - 6 = 21 - 6 = 15

Hence the first three terms of the AP is 1, 8, 15, ...

Hence this is the required series.

Answer 2

$\large\mathsf{Given \ -}$

${a_n}$ $\mathsf{= \ 7n - 6}$

$\large\mathsf\purple{Putting \ n \ = \ 1}$

${a_1}$ $\mathsf{= \ 7(1) - 6}$

${a_1}$ $\mathsf{= \ 1}$

$\large\mathsf\purple{Putting \ n \ = \ 2}$

${a_2}$ $\mathsf{= \ 7(2) - 6}$

${a_2}$ $\mathsf{= \ 8}$

$\large\mathsf\purple{Putting \ n \ = \ 3}$

${a_3}$ $\mathsf{= \ 7(3) - 6}$

${a_3}$ $\mathsf{= \ 15}$

$\huge\mathsf\red{Series \ -}$

$\huge\mathsf\blue{1, \ 8, \ 15, \ ..........}$