Question

The nth term of the AP. √2,2 √2, 3√2,...is

Answer 1

Step-by-step explanation:

Answer 2

Here is your answer...

$a = \sqrt{2} \\ d = 2 \sqrt{2} - \sqrt{2} = \sqrt{2 } \\ an = a + (n - 1)d \\ = \sqrt{2} + (n - 1) \sqrt{2} \\ = \sqrt{2} + \sqrt{2} n - \sqrt{2} \\ = \sqrt{2} n$