Question

the nth term of the AP 4 10 16 22 is​

Answer 1

$4 , 10, 16, 22 ,\ldots \: are \: in \: A.P$

$First \: term (a = a_{1}) = 4$

$Common \: difference (d) = a_{2} - a_{1}$

$= 10 - 4 \\= 6$

$\boxed{ \pink { n^{th} \: term (a_{n}) = a + (n-1)d }}$

$n^{th} \:term (a_{n}) = 4 + (n-1)\times 6$

$= 4 + 6n - 6 \\= 6n - 2$

Therefore.,

$\red{n^{th} \:term \: of \: (a_{n})}$

$\green { = 6n - 2 }$

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