The nth term of the Ap (X+y)2,(X2+y2),(x-y)2
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Answer:
Thus Tn= (x+y)² +(n-1)(-2xy)
Step-by-step explanation:
(x+y)²,(x²+y²),(x-y)²
This is an AP with a=(x+y)²
2nd term T2=x²+y²
So the common difference
d=x²+y²-(x+y)²
=x²+y²-(x²+y²+2xy)
d= -2xy
We know that nth term Tn=a+(n-1)*d
Thus Tn= (x+y)² +(n-1)(-2xy)
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