Question

The nth term of the Ap (X+y)2,(X2+y2),(x-y)2​

Answer 1

Answer:

Thus Tn= (x+y)² +(n-1)(-2xy)

Step-by-step explanation:

(x+y)²,(x²+y²),(x-y)²

This is an AP with a=(x+y)²

2nd term T2=x²+y²

So the common difference

d=x²+y²-(x+y)²

=x²+y²-(x²+y²+2xy)

d= -2xy

We know that nth term Tn=a+(n-1)*d

Thus Tn= (x+y)² +(n-1)(-2xy)