Question

the nth term of the sequence 1/3 , 2/5 , 3/7 , 4/9 , ..... is

Answer 1

Answer:

1*(2(1)+1)=1*(2+1)=1*3=3

2*(2(2)+1)=2*(4+1)=2*5=10

3*(2(3)+1)=3*(6+1)=3*7=21

4*(2(4)+1)=4*(8+1)=4*9=36

and if n=500

500*(2(500)+1)=500*(1000+1)=500*1001=500500

Answer 2

Answer:

1,3,5,7,9,... are in A.PFirst term = a = 1 Common difference d = 3 - 1 = 2 nth term = tn = a + (n - 1 )d tn = 1 + (n - 1 )2 = 1 + 2n - 2 = 2n - 1 nth term ...