Question

the nth terms.
Find the sum of the first 40 positive integers divisible by 6.
$\sqrt{2} + \sqrt{3} \: prove \: that \: irrational \: numbe$
​

Answer 1

Answer:

Wkt

Sn=n/2(2a+(n-1)d)

Step-by-step explanation:

S40= 40/2(2×6+(40-1)6)

= 20(12+39×6)

= 20(12+234)

= 20(246)

= 4920

Therefore ans = 4920

Answer 2

hope it's help u...........