Question

the nucleus of radium-226 decays to radium-222 by the emission of alpha particle he-4 of energy 4.8 MeV. if mass of rn-222=222.0amu and mass of he-4=4.003 amu then calculate the recoil

Answer 1

Question

the nucleus of radium-226 decays to radium-222 by the emission of alpha particle he-4 of energy 4.8 MeV. if mass of rn-222=222.0amu and mass of he-4=4.003 amu then calculate the recoil

to find:-

recoil

answer:-

$\large\rm { _{88} Ra^{226} \longrightarrow _{86} Rn^{222} </p><p>+ _{2} H^{4}}$

we know that

$\large\rm { K = \frac{p^{2}}{2m} }$

$\large\rm { \therefore p = \sqrt{2mk}}$

$\large\rm { \therefore mK = m_{ \alpha } K_{\alpha}}$

$\large\rm { K_{Rn} = \frac{m_{ \alpha } K_{\alpha}}{m_{Rn}} }$

$\large\rm { = 0.86666 \ MeV}$ is your answer.