Math, asked by ahana237, 2 months ago

The null sets in the following are
(1) The set A of all prime numbers lying
between 15 and 19.
(ii) A={x:x<5, x>6}
(iii) A = {x : x2 = 16, XEN}
(iv) A = {x:XEN,4<x<5}​

Answers

Answered by niharuk09
5

Answer:

(iv)A ={x.xEN,4<x<5}

Step-by-step explanation:

the reason is the in the first question the prime number 17 lies between 15 and 19. In the second the condition says X can be any number greater than 5 and 6 so there are many numbers from 7 to 00. In third it says x²=16 and x should be natural number where the answer is 4 which is a natural number. In the fourth it says X is natural number which is greater than 4 but less than five but natural number's do not have decimals between them and only decimal is possible to be formed

Hope, this helps

Answered by demoneye1220
0

hi brooooooooooooooooooo

true or false

Similar questions