Question

The numb of zeroes of the polynomial x3-3x2-x-3​

Answer 1

Step-by-step explanation:

x³-3x²-x-3=0

x(x²-3x-1-3)=0

x(x²-3x-4)=0

x(x²-(4-1)x-4)=0

x(x²-4x+x-4)=0

x²-4x+x-4=0

x(x-4)+1(x-4)=0

(x-4)(x+1) = 0

Either x = 4 or x = -1

Answer 2

Answer:

There are three zeroes

They are -3, 1, and -1.

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