Math, asked by ADITYAFF000000000000, 4 months ago

The number 100 a +10 b+c in usual form is

A) abc B) bca C) cab D) none of these​

Answers

Answered by riyaprajapati2100
9

A number can be expressed as the sum of the products of its digits with their respective place values

∴1000a+10b+c

=a×1000+0×100+b×10+c×1

=a0bc

Hence, option (C) is correct.

Answered by Anonymous
5

The number 100a+10b+c in usual form is abc. (Option a)

Given:

A number of the form 100a+10b+c

To find:

The number in its usual form

Solution:

We can find the solution by following the given steps-

We know that a number multiplied by 100 will be on the hundreds place, a number multiplied by 10 will be on the tens place, and a number multiplied by 1 will be on the ones place.

So, following this, 100a+10b+1c can be written as abc.

Here a is at the hundreds place, b at tens place, and c at ones place.

Therefore, the usual form of 100a+10b+c is abc.

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