The number 405 and 1960, written as the product of their prime factors, are
405= 3
4 × 5 and 1960= 2
3 × 5 × 7
2
. Hence, find
(i) the greatest whole number which is a factor of both 405 and 1960.
(ii) the smallest whole number that is divisible by both 405 and 1960.
Answers
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Step-by-step explanation:
405 = 3×135
= 3×3×45
= 3×3×3×15
= 3×3×3×3×5
1960 =2×980
=2×2×490
= 2×2×2×245
= 2×2×2×5×49
= 2×2×2×5×7×7
the greatest whole number is 5 and smallest whole number is also 5 which is factor of both 406 and 1960.
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