Question

The number 6221.12 can be expressed in words as

Answer 1

Let's take n=43361 and given that n=p

Let's take n=43361 and given that n=p 1

Let's take n=43361 and given that n=p 1

Let's take n=43361 and given that n=p 1 .p

Let's take n=43361 and given that n=p 1 .p 2

Let's take n=43361 and given that n=p 1 .p 2

Let's take n=43361 and given that n=p 1 .p 2 where p

Let's take n=43361 and given that n=p 1 .p 2 where p 1

Let's take n=43361 and given that n=p 1 .p 2 where p 1

Let's take n=43361 and given that n=p 1 .p 2 where p 1 , p

Let's take n=43361 and given that n=p 1 .p 2 where p 1 , p 2

Let's take n=43361 and given that n=p 1 .p 2 where p 1 , p 2

Let's take n=43361 and given that n=p 1 .p 2 where p 1 , p 2 are two prime numbers.

Let's take n=43361 and given that n=p 1 .p 2 where p 1 , p 2 are two prime numbers.and also given that there are 42900 numbers which are less than 43361 and are co-prime to it. Therefore from Euler's totient function ϕ which states as number of numbers which are less than n and co-prime to it and it is given by ϕ(n)=n−1 if n is prime else ϕ(n)=ϕ(p

1

1

1 ).ϕ(p

1 ).ϕ(p 2

1 ).ϕ(p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1 +p

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1 +p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1 +p 2

1 ).ϕ(p 2 ) if n is written as product of those two numbers.Now, ϕ(43361)=42900=(p 1 −1)(p 2 −1) ⟹ 42900=43361−(p 1 +p 2 )+1 ⟹ p 1 +p 2 =462