Math, asked by Outcastenation, 6 months ago

The number A8 is a two-digit number with tens digit A and units (ones) digit 8.
Similarly, 3B is a two-digit number with tens digit 3 and units digit B.
When A8 is multiplied by 3B, the result is the four-digit number C730. That is,

A8
× 3B
C730

If A, B, and C are each different digits from 0 to 9, determine the values of A,
B, and C.

Answers

Answered by tamannajaiswal5555
20

Answer:

A - 23

B - 14

C - 63

Please mark as brainliest it was very hard

Answered by PaTHEticaL
7

UR ANS DUDES

A- 23

B- 14

C- 63

^_^

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