The number are 90% and 75o. Lessar than a
thired number. By what percent should the
first number be increased to that it become
equal to the second number ?
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Two numbers are 90% and 75% lesser than a third number. By what % should the first number be increased so that it becomes equal to the second number?
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Well for simplicity we assume that the third number =100x
Let first no is x and it is 90% less then the third number
so a=100x-90x=10x
similarly second number y=100x-75x=25x
Now difference between the 2nd number and first number=25x-10x=15x
% of 15x against the 1st no 10x
=100*15x/10x=150 %
Thus 1st number should be increased by 150% so that is can become equal to
second number
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