Math, asked by sparmpreet543, 5 months ago

the number are in the ratio 7:11 if 7 is added to each other of the number the ratio become 2:3 find the number ​

Answers

Answered by Anonymous
8

\sf{\star} Correct Question:-

Two numbers are in the ratio 7:11. If 7 is added to both the numbers the ratio becomes 2:3. Find the numbers.

\sf{\star} Given:-

  • Two numbers are in the ratio = 7:11
  • When 7 is added to both the ratio becomes = 2:3

\sf{\star} To Find:-

The numbers.

\sf{\star} Assumption:-

Let the common multiples of the ratios be x

Therefore,

1st number = 7x

2nd number = 11x

\sf{\star} Solution:-

When 7 is added to both the number the ratio becomes 2:3

ATQ,

\sf{\dfrac{7x+7}{11x+7} = \dfrac{2}{3}}

= \sf{3(7x+7) = 2(11x+7)}

= \sf{21x + 21 = 22x + 14}

= \sf{21x - 22x = 14 - 21}

= \sf{-x = -7}

= \sf{x = 7}

Therefore,

The numbers are:-

1st number = 7x = 7×7 = 49

2nd number = 11x = 11×7 = 77

______________________________________

\sf{\star} Verification:-

The ratio of the two numbers should be 7:11

Therefore,

\sf{49:77}

= \sf{\dfrac{49}{77}}

Cancel both numerator and denominator by 7

= \sf{\dfrac{\cancel{49}}{\cancel{77}}}

= \sf{\dfrac{7}{11}}

= \sf{7:11}

Therefore the ratio of the numbers is 7:11 [Verified].

______________________________________

Answered by MissPerfect09
25

Here, as per the provided question we are said here to find the number, where there is given information....

But, in the question we can see that there's a bit mistake. So, first of all let us correct the question and then write the answer –

CORRECT QUESTION :

Two numbers are in the ratio 7:11. If 7 is added to each other of the numbers then the ratio becomes 2:3. Find the numbers.

GIVEN :

  • Two numbers are in the ratio as = 7:11

  • When a number (considered as 7) is is added to each each other of the number then, the ratio becomes as = 2:3

TO FIND :

  • The number = ?

(when the provided question is given there with an appropriate information).

STEP-BY-STEP EXPLAINATION :

Now, there is given two numbers in the ratio as 7 and 11, When they're considered after putting as x, then we'll write them respectively as –

⟼ First number (7) = 7 × x = 7x

⟼ Second number (11) = 11 × x = 11x

Hence, we will simplify now as per the provided question (with taking as 'x')

⟹ \:  \frac{7 \rm {x} \:  +  \: 7 }{11 \rm {x} \:  +  \: 7}  =  \:  \frac{2}{3}

Now, solving here in the type of equation

'L.H.S = R.H.S' Rule –

⟹ \: 3(7 \rm {x} \:  +  \: 7) \: = 2(11 \rm {x} \:  +  \: 7)

⟹ \: 21 \rm {x} \:  +  \: 21 \:  =  \: 22 \rm {x} \:  +  \: 14

⟹ \: 21 \rm {x} \:  -  \: 22 \rm {x} \:  =  \: 14 \:  -  \: 21

⟹ \rm { - x} \:  =  \:  - 7

⟹ \rm {x} \:  =  \: 7

Hence,

We have got here the numbers as (after solving this question in the form of equation) –

⟼ First number = (7) = 7 × 7 = 49

⟼ Second number = (11) = 11 × 7 = 77

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