The number between 800 and 900 divisible completely by 13 and 17 is
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first we need to find the nearest number greater than 300300 which is divisible by 17.
i.e 306=17∗18306=17∗18.
And then the nearest number less than 900900i.e. 884884.
Now, by using the nthnthterm formula of an A.P., we get
306+(n−1)17=884306+(n−1)17=884( where n is the no. of terms lying between 300 and 900 which is divisible by 17)
By computing the above we get,
n=35
i.e 306=17∗18306=17∗18.
And then the nearest number less than 900900i.e. 884884.
Now, by using the nthnthterm formula of an A.P., we get
306+(n−1)17=884306+(n−1)17=884( where n is the no. of terms lying between 300 and 900 which is divisible by 17)
By computing the above we get,
n=35
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