Question

The number consist of two digits of which the tens digit exceeds the ones digit by 3.The number is equal to 7 times the sum of the digit . Find the number

Answer 1

Hi friend
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Your answer
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Let the number at the units place be x.
Then, the number at the tens place will be = (x + 3)

So,
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According to the question,
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10(x+3) + x = 7( x+3 + x)

10x + 30 + x = 7x + 21 + 7x

11x - 14x = 21 - 30

-3x = -9

3x = 9

x = 9/3

x = 3

Then,
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Tens digit = (x+3) = (3+3) = 6

Therefore,
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The number is = 63

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