The number formed by reversing the digits of a two-digit number exceeds the original number by 20%. What is the absolute difference between the digits of the number?
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Answer:
1 (imp.)
Step-by-step explanation:
let O. 2 digits no. = 10x + y
on Reversing the digits ,
New no. = 10y + x
10x+y + 20% of (10x+ y) = 10y + x
10x + y +2x + 0.2y = 10y + x
11x = 8.8y => 110x = 88y
x/y = 8/10 = 4/5
absolute difference between the digits of the number will be
= 5 - 4 = 1
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