Question

The number formed when a three-digit number reversed is 396 more than the original number if the tens digit of x is 2 and its hundreds digit is halt the units digit, find x

Answer 1

hi,

Let's assume

a the digit of hundreds

b the digit of tens

2a the digit of units.

$\overline{ab(2a)}=100*a+10*b+2a=102*a+20\ (since\ b=2)\\\\ \overline{(2a)ba)}=\overline{ab(2a)}+396\Rightarrow\ 200*a+10*b+a=102*a+10*b+396\\\\ \Rightarrow\ 99*a=396\\\\ \Rightarrow\ a=4$

x=428