The number formed when a three digit number x is reversed is 396 more than the original number.if the tens digit of x is 2 and its hundreds digit is half the units digit,find x
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let u=units digit
let t=tens digit
let h=hundreds digit
..
h=3u
u+t+h=15
original number: 100h+10t+u
reversed number:100u+10t+h
original number-reversed number=396
(100h+10t+u)-(100u+10t+h)=396
100h+10t+u-100u-10t-h=396
99h-99u=396
99(3u)-99u=396
2u*99=396
u=396/2*99=2
h=3u=6
t=15-t+h=15-8=7
ans:
number: 672
let t=tens digit
let h=hundreds digit
..
h=3u
u+t+h=15
original number: 100h+10t+u
reversed number:100u+10t+h
original number-reversed number=396
(100h+10t+u)-(100u+10t+h)=396
100h+10t+u-100u-10t-h=396
99h-99u=396
99(3u)-99u=396
2u*99=396
u=396/2*99=2
h=3u=6
t=15-t+h=15-8=7
ans:
number: 672
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