Question

The number in
unit place in 3^1969​

Answer 1

Answer:9

Step-by-step explanation:

Now...............................let’s see

3 to the power of 1 ends with a 3. (3)

3 to the power of 2 ends with a 9. (9)

3 to the power of 3 ends with a 7. (27)

3 to the power of 4 ends with a 1. (81)

3 to the power of 5 ends with a 3 AGAIN. (243)

3 to the power of 6 ends with a 9 AGAIN. (729)

So we see the pattern ie 3,9,7,1.....

So now let’s divide 1969 by 4 and see what remainder we get

We get remainder 1. Thus, the ending number will be 9. Because 9 is second in the order of the pattern

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Answer 2

Answer :-

3

Solution :-

${3}^{4n \:} - 1$

${3}^{4n + 1} \: - 3$

${3}^{4n + 2} \: - 9$

${3}^{4n + 3} \: - 7$

1969/4 leaves remainder 1 which will be 3^(4n+1).

Therefore, units digit here is 3.