The number obtained by reversing a two digit number is 18 more than the original number. If the sum of its digits is 8. find the number
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Answered by
51
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Krishna5499:
answer is 35. thank you at least you try
no my answer is correct
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Answered by
18
Let The ten's digit be n and one's be y
Number = 10n + y
ATQ
X + Y = 8 _________1.
10N + Y = 18 + (10y + x)
10N + Y = 10Y -N = 18
9X -9Y = 18
Subtracting 1. From 2
-Y = 2
+ Y = 8
+ 2Y = +6
Y= 3
So the number Y = 10*5+ 3
= 50+3 = 53
2) Putting the value of Y in 1
N+3= 8
N=8-3
N=5.
Number = 10n + y
ATQ
X + Y = 8 _________1.
10N + Y = 18 + (10y + x)
10N + Y = 10Y -N = 18
9X -9Y = 18
Subtracting 1. From 2
-Y = 2
+ Y = 8
+ 2Y = +6
Y= 3
So the number Y = 10*5+ 3
= 50+3 = 53
2) Putting the value of Y in 1
N+3= 8
N=8-3
N=5.
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answer is 35. your answer is wrong. thank you at least you try to help me
It Is Not Wrong It Is Correct.
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